4(b-2)=b+3b-8

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Solution for 4(b-2)=b+3b-8 equation:


Simplifying
4(b + -2) = b + 3b + -8

Reorder the terms:
4(-2 + b) = b + 3b + -8
(-2 * 4 + b * 4) = b + 3b + -8
(-8 + 4b) = b + 3b + -8

Reorder the terms:
-8 + 4b = -8 + b + 3b

Combine like terms: b + 3b = 4b
-8 + 4b = -8 + 4b

Add '8' to each side of the equation.
-8 + 8 + 4b = -8 + 8 + 4b

Combine like terms: -8 + 8 = 0
0 + 4b = -8 + 8 + 4b
4b = -8 + 8 + 4b

Combine like terms: -8 + 8 = 0
4b = 0 + 4b
4b = 4b

Add '-4b' to each side of the equation.
4b + -4b = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 4b + -4b

Combine like terms: 4b + -4b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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