4(b-3)*2.3b=4b

Solution for 4(b-3)*2.3b=4b equation:

4(b-3)*2.3b=4b

We move all terms to the left:

4(b-3)*2.3b-(4b)=0

We add all the numbers together, and all the variables

-4b+4(b-3)*2.3b=0

We multiply parentheses

8b^2-4b-24b=0

We add all the numbers together, and all the variables

8b^2-28b=0

a = 8; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·8·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*8}=\frac{0}{16}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*8}=\frac{56}{16}
=3+1/2
$