4(b-3)+9=21

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Solution for 4(b-3)+9=21 equation: 



4(b-3)+9=21

We move all terms to the left:

4(b-3)+9-(21)=0

We add all the numbers together, and all the variables

4(b-3)-12=0

We multiply parentheses

4b-12-12=0

We add all the numbers together, and all the variables

4b-24=0

We move all terms containing b to the left, all other terms to the right

4b=24

b=24/4

b=6

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