4(b-3)-5=11

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Solution for 4(b-3)-5=11 equation: 



4(b-3)-5=11

We move all terms to the left:

4(b-3)-5-(11)=0

We add all the numbers together, and all the variables

4(b-3)-16=0

We multiply parentheses

4b-12-16=0

We add all the numbers together, and all the variables

4b-28=0

We move all terms containing b to the left, all other terms to the right

4b=28

b=28/4

b=7

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