4(b-3)-6=2(b+5)

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Solution for 4(b-3)-6=2(b+5) equation:


Simplifying
4(b + -3) + -6 = 2(b + 5)

Reorder the terms:
4(-3 + b) + -6 = 2(b + 5)
(-3 * 4 + b * 4) + -6 = 2(b + 5)
(-12 + 4b) + -6 = 2(b + 5)

Reorder the terms:
-12 + -6 + 4b = 2(b + 5)

Combine like terms: -12 + -6 = -18
-18 + 4b = 2(b + 5)

Reorder the terms:
-18 + 4b = 2(5 + b)
-18 + 4b = (5 * 2 + b * 2)
-18 + 4b = (10 + 2b)

Solving
-18 + 4b = 10 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-18 + 4b + -2b = 10 + 2b + -2b

Combine like terms: 4b + -2b = 2b
-18 + 2b = 10 + 2b + -2b

Combine like terms: 2b + -2b = 0
-18 + 2b = 10 + 0
-18 + 2b = 10

Add '18' to each side of the equation.
-18 + 18 + 2b = 10 + 18

Combine like terms: -18 + 18 = 0
0 + 2b = 10 + 18
2b = 10 + 18

Combine like terms: 10 + 18 = 28
2b = 28

Divide each side by '2'.
b = 14

Simplifying
b = 14

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