4(b-3)=4b+-12

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Solution for 4(b-3)=4b+-12 equation: 



4(b-3)=4b+-12

We move all terms to the left:

4(b-3)-(4b+-12)=0

We add all the numbers together, and all the variables

4(b-3)-(4b-12)=0

We multiply parentheses

4b-(4b-12)-12=0

We get rid of parentheses

4b-4b+12-12=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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