4(b-3)=4b+12

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Solution for 4(b-3)=4b+12 equation:



4(b-3)=4b+12
We move all terms to the left:
4(b-3)-(4b+12)=0
We multiply parentheses
4b-(4b+12)-12=0
We get rid of parentheses
4b-4b-12-12=0
We add all the numbers together, and all the variables
-24!=0
There is no solution for this equation

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