4(b-4)-10=2(b-3)

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Solution for 4(b-4)-10=2(b-3) equation: 



4(b-4)-10=2(b-3)

We move all terms to the left:

4(b-4)-10-(2(b-3))=0

We multiply parentheses

4b-(2(b-3))-16-10=0



We calculate terms in parentheses: -(2(b-3)), so:

2(b-3)

We multiply parentheses

2b-6

Back to the equation:

-(2b-6)



We add all the numbers together, and all the variables

4b-(2b-6)-26=0

We get rid of parentheses

4b-2b+6-26=0

We add all the numbers together, and all the variables

2b-20=0

We move all terms containing b to the left, all other terms to the right

2b=20

b=20/2

b=10

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