4(b-4)-2(b+4)=6

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Solution for 4(b-4)-2(b+4)=6 equation:



4(b-4)-2(b+4)=6
We move all terms to the left:
4(b-4)-2(b+4)-(6)=0
We multiply parentheses
4b-2b-16-8-6=0
We add all the numbers together, and all the variables
2b-30=0
We move all terms containing b to the left, all other terms to the right
2b=30
b=30/2
b=15

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