4(b-4)=16+6b

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Solution for 4(b-4)=16+6b equation: 



4(b-4)=16+6b

We move all terms to the left:

4(b-4)-(16+6b)=0

We add all the numbers together, and all the variables

4(b-4)-(6b+16)=0

We multiply parentheses

4b-(6b+16)-16=0

We get rid of parentheses

4b-6b-16-16=0

We add all the numbers together, and all the variables

-2b-32=0

We move all terms containing b to the left, all other terms to the right

-2b=32

b=32/-2

b=-16

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