4(b-5)+2b=3b+1

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Solution for 4(b-5)+2b=3b+1 equation: 



4(b-5)+2b=3b+1

We move all terms to the left:

4(b-5)+2b-(3b+1)=0

We add all the numbers together, and all the variables

2b+4(b-5)-(3b+1)=0

We multiply parentheses

2b+4b-(3b+1)-20=0

We get rid of parentheses

2b+4b-3b-1-20=0

We add all the numbers together, and all the variables

3b-21=0

We move all terms containing b to the left, all other terms to the right

3b=21

b=21/3

b=7

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