4(b-5)-3(2b-5)=2(3b-1)-27

Solution for 4(b-5)-3(2b-5)=2(3b-1)-27 equation:

4(b-5)-3(2b-5)=2(3b-1)-27

We move all terms to the left:

4(b-5)-3(2b-5)-(2(3b-1)-27)=0

We multiply parentheses

4b-6b-(2(3b-1)-27)-20+15=0


We calculate terms in parentheses: -(2(3b-1)-27), so:

2(3b-1)-27

We multiply parentheses

6b-2-27

We add all the numbers together, and all the variables

6b-29

Back to the equation:

-(6b-29)


We add all the numbers together, and all the variables

-2b-(6b-29)-5=0

We get rid of parentheses

-2b-6b+29-5=0

We add all the numbers together, and all the variables

-8b+24=0

We move all terms containing b to the left, all other terms to the right

-8b=-24

b=-24/-8

b=+3