4(b-5)=2(b+3)

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Solution for 4(b-5)=2(b+3) equation:


Simplifying
4(b + -5) = 2(b + 3)

Reorder the terms:
4(-5 + b) = 2(b + 3)
(-5 * 4 + b * 4) = 2(b + 3)
(-20 + 4b) = 2(b + 3)

Reorder the terms:
-20 + 4b = 2(3 + b)
-20 + 4b = (3 * 2 + b * 2)
-20 + 4b = (6 + 2b)

Solving
-20 + 4b = 6 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-20 + 4b + -2b = 6 + 2b + -2b

Combine like terms: 4b + -2b = 2b
-20 + 2b = 6 + 2b + -2b

Combine like terms: 2b + -2b = 0
-20 + 2b = 6 + 0
-20 + 2b = 6

Add '20' to each side of the equation.
-20 + 20 + 2b = 6 + 20

Combine like terms: -20 + 20 = 0
0 + 2b = 6 + 20
2b = 6 + 20

Combine like terms: 6 + 20 = 26
2b = 26

Divide each side by '2'.
b = 13

Simplifying
b = 13

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