4(b-5)=5(b-4)

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Solution for 4(b-5)=5(b-4) equation:


Simplifying
4(b + -5) = 5(b + -4)

Reorder the terms:
4(-5 + b) = 5(b + -4)
(-5 * 4 + b * 4) = 5(b + -4)
(-20 + 4b) = 5(b + -4)

Reorder the terms:
-20 + 4b = 5(-4 + b)
-20 + 4b = (-4 * 5 + b * 5)
-20 + 4b = (-20 + 5b)

Add '20' to each side of the equation.
-20 + 20 + 4b = -20 + 20 + 5b

Combine like terms: -20 + 20 = 0
0 + 4b = -20 + 20 + 5b
4b = -20 + 20 + 5b

Combine like terms: -20 + 20 = 0
4b = 0 + 5b
4b = 5b

Solving
4b = 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
4b + -5b = 5b + -5b

Combine like terms: 4b + -5b = -1b
-1b = 5b + -5b

Combine like terms: 5b + -5b = 0
-1b = 0

Divide each side by '-1'.
b = 0

Simplifying
b = 0

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