4(b-6)=6b+12

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Solution for 4(b-6)=6b+12 equation: 



4(b-6)=6b+12

We move all terms to the left:

4(b-6)-(6b+12)=0

We multiply parentheses

4b-(6b+12)-24=0

We get rid of parentheses

4b-6b-12-24=0

We add all the numbers together, and all the variables

-2b-36=0

We move all terms containing b to the left, all other terms to the right

-2b=36

b=36/-2

b=-18

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