4(b-7)=2b+8

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Solution for 4(b-7)=2b+8 equation: 



4(b-7)=2b+8

We move all terms to the left:

4(b-7)-(2b+8)=0

We multiply parentheses

4b-(2b+8)-28=0

We get rid of parentheses

4b-2b-8-28=0

We add all the numbers together, and all the variables

2b-36=0

We move all terms containing b to the left, all other terms to the right

2b=36

b=36/2

b=18

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