4(c+-3)+-6=10

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Solution for 4(c+-3)+-6=10 equation: 



4(c+-3)+-6=10

We move all terms to the left:

4(c+-3)+-6-(10)=0

determiningTheFunctionDomain
4(c+-3)-6-10+=0

We add all the numbers together, and all the variables

4(c-3)-6-10+=0

We add all the numbers together, and all the variables

4(c-3)=0

We multiply parentheses

4c-12=0

We move all terms containing c to the left, all other terms to the right

4c=12

c=12/4

c=3

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