4(c+-7)+12=20

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Solution for 4(c+-7)+12=20 equation: 



4(c+-7)+12=20

We move all terms to the left:

4(c+-7)+12-(20)=0

We add all the numbers together, and all the variables

4(c-7)+12-20=0

We add all the numbers together, and all the variables

4(c-7)-8=0

We multiply parentheses

4c-28-8=0

We add all the numbers together, and all the variables

4c-36=0

We move all terms containing c to the left, all other terms to the right

4c=36

c=36/4

c=9

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