4(c+1)+2c+3(c-1)=25

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Solution for 4(c+1)+2c+3(c-1)=25 equation: 


Simplifying
4(c + 1) + 2c + 3(c + -1) = 25

Reorder the terms:
4(1 + c) + 2c + 3(c + -1) = 25
(1 * 4 + c * 4) + 2c + 3(c + -1) = 25
(4 + 4c) + 2c + 3(c + -1) = 25

Reorder the terms:
4 + 4c + 2c + 3(-1 + c) = 25
4 + 4c + 2c + (-1 * 3 + c * 3) = 25
4 + 4c + 2c + (-3 + 3c) = 25

Reorder the terms:
4 + -3 + 4c + 2c + 3c = 25

Combine like terms: 4 + -3 = 1
1 + 4c + 2c + 3c = 25

Combine like terms: 4c + 2c = 6c
1 + 6c + 3c = 25

Combine like terms: 6c + 3c = 9c
1 + 9c = 25

Solving
1 + 9c = 25

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 9c = 25 + -1

Combine like terms: 1 + -1 = 0
0 + 9c = 25 + -1
9c = 25 + -1

Combine like terms: 25 + -1 = 24
9c = 24

Divide each side by '9'.
c = 2.666666667

Simplifying
c = 2.666666667

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