4(c+1)+2c=7+3(c+1)

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Solution for 4(c+1)+2c=7+3(c+1) equation:


Simplifying
4(c + 1) + 2c = 7 + 3(c + 1)

Reorder the terms:
4(1 + c) + 2c = 7 + 3(c + 1)
(1 * 4 + c * 4) + 2c = 7 + 3(c + 1)
(4 + 4c) + 2c = 7 + 3(c + 1)

Combine like terms: 4c + 2c = 6c
4 + 6c = 7 + 3(c + 1)

Reorder the terms:
4 + 6c = 7 + 3(1 + c)
4 + 6c = 7 + (1 * 3 + c * 3)
4 + 6c = 7 + (3 + 3c)

Combine like terms: 7 + 3 = 10
4 + 6c = 10 + 3c

Solving
4 + 6c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
4 + 6c + -3c = 10 + 3c + -3c

Combine like terms: 6c + -3c = 3c
4 + 3c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
4 + 3c = 10 + 0
4 + 3c = 10

Add '-4' to each side of the equation.
4 + -4 + 3c = 10 + -4

Combine like terms: 4 + -4 = 0
0 + 3c = 10 + -4
3c = 10 + -4

Combine like terms: 10 + -4 = 6
3c = 6

Divide each side by '3'.
c = 2

Simplifying
c = 2

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