4(c+1)=3(2c-4)

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Solution for 4(c+1)=3(2c-4) equation:


Simplifying
4(c + 1) = 3(2c + -4)

Reorder the terms:
4(1 + c) = 3(2c + -4)
(1 * 4 + c * 4) = 3(2c + -4)
(4 + 4c) = 3(2c + -4)

Reorder the terms:
4 + 4c = 3(-4 + 2c)
4 + 4c = (-4 * 3 + 2c * 3)
4 + 4c = (-12 + 6c)

Solving
4 + 4c = -12 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
4 + 4c + -6c = -12 + 6c + -6c

Combine like terms: 4c + -6c = -2c
4 + -2c = -12 + 6c + -6c

Combine like terms: 6c + -6c = 0
4 + -2c = -12 + 0
4 + -2c = -12

Add '-4' to each side of the equation.
4 + -4 + -2c = -12 + -4

Combine like terms: 4 + -4 = 0
0 + -2c = -12 + -4
-2c = -12 + -4

Combine like terms: -12 + -4 = -16
-2c = -16

Divide each side by '-2'.
c = 8

Simplifying
c = 8

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