4(c+1)whenc=2

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Solution for 4(c+1)whenc=2 equation:


Simplifying
4(c + 1) * whenc = 2

Reorder the terms:
4(1 + c) * whenc = 2

Reorder the terms for easier multiplication:
4cehnw(1 + c) = 2
(1 * 4cehnw + c * 4cehnw) = 2
(4cehnw + 4c2ehnw) = 2

Solving
4cehnw + 4c2ehnw = 2

Solving for variable 'c'.

Reorder the terms:
-2 + 4cehnw + 4c2ehnw = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 4cehnw + 4c2ehnw = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-1 + 2cehnw + 2c2ehnw) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-1 + 2cehnw + 2c2ehnw)' equal to zero and attempt to solve: Simplifying -1 + 2cehnw + 2c2ehnw = 0 Solving -1 + 2cehnw + 2c2ehnw = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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