4(c+10)-146=6(2c+9)

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Solution for 4(c+10)-146=6(2c+9) equation:


Simplifying
4(c + 10) + -146 = 6(2c + 9)

Reorder the terms:
4(10 + c) + -146 = 6(2c + 9)
(10 * 4 + c * 4) + -146 = 6(2c + 9)
(40 + 4c) + -146 = 6(2c + 9)

Reorder the terms:
40 + -146 + 4c = 6(2c + 9)

Combine like terms: 40 + -146 = -106
-106 + 4c = 6(2c + 9)

Reorder the terms:
-106 + 4c = 6(9 + 2c)
-106 + 4c = (9 * 6 + 2c * 6)
-106 + 4c = (54 + 12c)

Solving
-106 + 4c = 54 + 12c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12c' to each side of the equation.
-106 + 4c + -12c = 54 + 12c + -12c

Combine like terms: 4c + -12c = -8c
-106 + -8c = 54 + 12c + -12c

Combine like terms: 12c + -12c = 0
-106 + -8c = 54 + 0
-106 + -8c = 54

Add '106' to each side of the equation.
-106 + 106 + -8c = 54 + 106

Combine like terms: -106 + 106 = 0
0 + -8c = 54 + 106
-8c = 54 + 106

Combine like terms: 54 + 106 = 160
-8c = 160

Divide each side by '-8'.
c = -20

Simplifying
c = -20

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