4(c+12)=-18

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Solution for 4(c+12)=-18 equation: 



4(c+12)=-18

We move all terms to the left:

4(c+12)-(-18)=0

We add all the numbers together, and all the variables

4(c+12)+18=0

We multiply parentheses

4c+48+18=0

We add all the numbers together, and all the variables

4c+66=0

We move all terms containing c to the left, all other terms to the right

4c=-66

c=-66/4

c=-16+1/2

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