4(c+12)=-18

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Solution for 4(c+12)=-18 equation:



4(c+12)=-18
We move all terms to the left:
4(c+12)-(-18)=0
We add all the numbers together, and all the variables
4(c+12)+18=0
We multiply parentheses
4c+48+18=0
We add all the numbers together, and all the variables
4c+66=0
We move all terms containing c to the left, all other terms to the right
4c=-66
c=-66/4
c=-16+1/2

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