4(c+12)=12c+18

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Solution for 4(c+12)=12c+18 equation: 



4(c+12)=12c+18

We move all terms to the left:

4(c+12)-(12c+18)=0

We multiply parentheses

4c-(12c+18)+48=0

We get rid of parentheses

4c-12c-18+48=0

We add all the numbers together, and all the variables

-8c+30=0

We move all terms containing c to the left, all other terms to the right

-8c=-30

c=-30/-8

c=3+3/4

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