4(c+12)=2c+18-15

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Solution for 4(c+12)=2c+18-15 equation: 



4(c+12)=2c+18-15

We move all terms to the left:

4(c+12)-(2c+18-15)=0

We add all the numbers together, and all the variables

4(c+12)-(2c+3)=0

We multiply parentheses

4c-(2c+3)+48=0

We get rid of parentheses

4c-2c-3+48=0

We add all the numbers together, and all the variables

2c+45=0

We move all terms containing c to the left, all other terms to the right

2c=-45

c=-45/2

c=-22+1/2

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