4(c+12)=6(k+2)

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Solution for 4(c+12)=6(k+2) equation:


Simplifying
4(c + 12) = 6(k + 2)

Reorder the terms:
4(12 + c) = 6(k + 2)
(12 * 4 + c * 4) = 6(k + 2)
(48 + 4c) = 6(k + 2)

Reorder the terms:
48 + 4c = 6(2 + k)
48 + 4c = (2 * 6 + k * 6)
48 + 4c = (12 + 6k)

Solving
48 + 4c = 12 + 6k

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-48' to each side of the equation.
48 + -48 + 4c = 12 + -48 + 6k

Combine like terms: 48 + -48 = 0
0 + 4c = 12 + -48 + 6k
4c = 12 + -48 + 6k

Combine like terms: 12 + -48 = -36
4c = -36 + 6k

Divide each side by '4'.
c = -9 + 1.5k

Simplifying
c = -9 + 1.5k

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