4(c+2)-17=35

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Solution for 4(c+2)-17=35 equation: 



4(c+2)-17=35

We move all terms to the left:

4(c+2)-17-(35)=0

We add all the numbers together, and all the variables

4(c+2)-52=0

We multiply parentheses

4c+8-52=0

We add all the numbers together, and all the variables

4c-44=0

We move all terms containing c to the left, all other terms to the right

4c=44

c=44/4

c=11

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