4(c+2)-2(c+5)=14

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Solution for 4(c+2)-2(c+5)=14 equation:



4(c+2)-2(c+5)=14
We move all terms to the left:
4(c+2)-2(c+5)-(14)=0
We multiply parentheses
4c-2c+8-10-14=0
We add all the numbers together, and all the variables
2c-16=0
We move all terms containing c to the left, all other terms to the right
2c=16
c=16/2
c=8

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