4(c+2)-3=6c-2(-4+c)

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Solution for 4(c+2)-3=6c-2(-4+c) equation: 



4(c+2)-3=6c-2(-4+c)

We move all terms to the left:

4(c+2)-3-(6c-2(-4+c))=0

We add all the numbers together, and all the variables

4(c+2)-(6c-2(c-4))-3=0

We multiply parentheses

4c-(6c-2(c-4))+8-3=0



We calculate terms in parentheses: -(6c-2(c-4)), so:

6c-2(c-4)

We multiply parentheses

6c-2c+8

We add all the numbers together, and all the variables

4c+8

Back to the equation:

-(4c+8)



We add all the numbers together, and all the variables

4c-(4c+8)+5=0

We get rid of parentheses

4c-4c-8+5=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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