4(c+2)-5=-21

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Solution for 4(c+2)-5=-21 equation: 



4(c+2)-5=-21

We move all terms to the left:

4(c+2)-5-(-21)=0

We add all the numbers together, and all the variables

4(c+2)+16=0

We multiply parentheses

4c+8+16=0

We add all the numbers together, and all the variables

4c+24=0

We move all terms containing c to the left, all other terms to the right

4c=-24

c=-24/4

c=-6

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