4(c+2)=3(c-2)

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Solution for 4(c+2)=3(c-2) equation: 



4(c+2)=3(c-2)

We move all terms to the left:

4(c+2)-(3(c-2))=0

We multiply parentheses

4c-(3(c-2))+8=0



We calculate terms in parentheses: -(3(c-2)), so:

3(c-2)

We multiply parentheses

3c-6

Back to the equation:

-(3c-6)



We get rid of parentheses

4c-3c+6+8=0

We add all the numbers together, and all the variables

c+14=0

We move all terms containing c to the left, all other terms to the right

c=-14

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