4(c+2)=6(c-2)

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Solution for 4(c+2)=6(c-2) equation: 



4(c+2)=6(c-2)

We move all terms to the left:

4(c+2)-(6(c-2))=0

We multiply parentheses

4c-(6(c-2))+8=0



We calculate terms in parentheses: -(6(c-2)), so:

6(c-2)

We multiply parentheses

6c-12

Back to the equation:

-(6c-12)



We get rid of parentheses

4c-6c+12+8=0

We add all the numbers together, and all the variables

-2c+20=0

We move all terms containing c to the left, all other terms to the right

-2c=-20

c=-20/-2

c=+10

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