4(c+3)+8=4c+20

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Solution for 4(c+3)+8=4c+20 equation: 



4(c+3)+8=4c+20

We move all terms to the left:

4(c+3)+8-(4c+20)=0

We multiply parentheses

4c-(4c+20)+12+8=0

We get rid of parentheses

4c-4c-20+12+8=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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