4(c+3)-(c-1)=64

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Solution for 4(c+3)-(c-1)=64 equation:


Simplifying
4(c + 3) + -1(c + -1) = 64

Reorder the terms:
4(3 + c) + -1(c + -1) = 64
(3 * 4 + c * 4) + -1(c + -1) = 64
(12 + 4c) + -1(c + -1) = 64

Reorder the terms:
12 + 4c + -1(-1 + c) = 64
12 + 4c + (-1 * -1 + c * -1) = 64
12 + 4c + (1 + -1c) = 64

Reorder the terms:
12 + 1 + 4c + -1c = 64

Combine like terms: 12 + 1 = 13
13 + 4c + -1c = 64

Combine like terms: 4c + -1c = 3c
13 + 3c = 64

Solving
13 + 3c = 64

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 3c = 64 + -13

Combine like terms: 13 + -13 = 0
0 + 3c = 64 + -13
3c = 64 + -13

Combine like terms: 64 + -13 = 51
3c = 51

Divide each side by '3'.
c = 17

Simplifying
c = 17

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