4(c+3)-(c-10)=64

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Solution for 4(c+3)-(c-10)=64 equation: 



4(c+3)-(c-10)=64

We move all terms to the left:

4(c+3)-(c-10)-(64)=0

We multiply parentheses

4c-(c-10)+12-64=0

We get rid of parentheses

4c-c+10+12-64=0

We add all the numbers together, and all the variables

3c-42=0

We move all terms containing c to the left, all other terms to the right

3c=42

c=42/3

c=14

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