4(c+3)=15+2(2c-1)

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Solution for 4(c+3)=15+2(2c-1) equation:


Simplifying
4(c + 3) = 15 + 2(2c + -1)

Reorder the terms:
4(3 + c) = 15 + 2(2c + -1)
(3 * 4 + c * 4) = 15 + 2(2c + -1)
(12 + 4c) = 15 + 2(2c + -1)

Reorder the terms:
12 + 4c = 15 + 2(-1 + 2c)
12 + 4c = 15 + (-1 * 2 + 2c * 2)
12 + 4c = 15 + (-2 + 4c)

Combine like terms: 15 + -2 = 13
12 + 4c = 13 + 4c

Add '-4c' to each side of the equation.
12 + 4c + -4c = 13 + 4c + -4c

Combine like terms: 4c + -4c = 0
12 + 0 = 13 + 4c + -4c
12 = 13 + 4c + -4c

Combine like terms: 4c + -4c = 0
12 = 13 + 0
12 = 13

Solving
12 = 13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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