4(c+3)=2c+18

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Solution for 4(c+3)=2c+18 equation: 



4(c+3)=2c+18

We move all terms to the left:

4(c+3)-(2c+18)=0

We multiply parentheses

4c-(2c+18)+12=0

We get rid of parentheses

4c-2c-18+12=0

We add all the numbers together, and all the variables

2c-6=0

We move all terms containing c to the left, all other terms to the right

2c=6

c=6/2

c=3

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