4(c+4)-3(c-4)=24

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Solution for 4(c+4)-3(c-4)=24 equation:



4(c+4)-3(c-4)=24
We move all terms to the left:
4(c+4)-3(c-4)-(24)=0
We multiply parentheses
4c-3c+16+12-24=0
We add all the numbers together, and all the variables
c+4=0
We move all terms containing c to the left, all other terms to the right
c=-4

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