4(c+4)=2c+2(c+8)

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Solution for 4(c+4)=2c+2(c+8) equation:


Simplifying
4(c + 4) = 2c + 2(c + 8)

Reorder the terms:
4(4 + c) = 2c + 2(c + 8)
(4 * 4 + c * 4) = 2c + 2(c + 8)
(16 + 4c) = 2c + 2(c + 8)

Reorder the terms:
16 + 4c = 2c + 2(8 + c)
16 + 4c = 2c + (8 * 2 + c * 2)
16 + 4c = 2c + (16 + 2c)

Reorder the terms:
16 + 4c = 16 + 2c + 2c

Combine like terms: 2c + 2c = 4c
16 + 4c = 16 + 4c

Add '-16' to each side of the equation.
16 + -16 + 4c = 16 + -16 + 4c

Combine like terms: 16 + -16 = 0
0 + 4c = 16 + -16 + 4c
4c = 16 + -16 + 4c

Combine like terms: 16 + -16 = 0
4c = 0 + 4c
4c = 4c

Add '-4c' to each side of the equation.
4c + -4c = 4c + -4c

Combine like terms: 4c + -4c = 0
0 = 4c + -4c

Combine like terms: 4c + -4c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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