4(c+5)+31=45

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Solution for 4(c+5)+31=45 equation: 



4(c+5)+31=45

We move all terms to the left:

4(c+5)+31-(45)=0

We add all the numbers together, and all the variables

4(c+5)-14=0

We multiply parentheses

4c+20-14=0

We add all the numbers together, and all the variables

4c+6=0

We move all terms containing c to the left, all other terms to the right

4c=-6

c=-6/4

c=-1+1/2

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