4(c+5)+4c=7(c+3)

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Solution for 4(c+5)+4c=7(c+3) equation:


Simplifying
4(c + 5) + 4c = 7(c + 3)

Reorder the terms:
4(5 + c) + 4c = 7(c + 3)
(5 * 4 + c * 4) + 4c = 7(c + 3)
(20 + 4c) + 4c = 7(c + 3)

Combine like terms: 4c + 4c = 8c
20 + 8c = 7(c + 3)

Reorder the terms:
20 + 8c = 7(3 + c)
20 + 8c = (3 * 7 + c * 7)
20 + 8c = (21 + 7c)

Solving
20 + 8c = 21 + 7c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7c' to each side of the equation.
20 + 8c + -7c = 21 + 7c + -7c

Combine like terms: 8c + -7c = 1c
20 + 1c = 21 + 7c + -7c

Combine like terms: 7c + -7c = 0
20 + 1c = 21 + 0
20 + 1c = 21

Add '-20' to each side of the equation.
20 + -20 + 1c = 21 + -20

Combine like terms: 20 + -20 = 0
0 + 1c = 21 + -20
1c = 21 + -20

Combine like terms: 21 + -20 = 1
1c = 1

Divide each side by '1'.
c = 1

Simplifying
c = 1

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