4(c+5)=2(4-c)

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Solution for 4(c+5)=2(4-c) equation: 



4(c+5)=2(4-c)

We move all terms to the left:

4(c+5)-(2(4-c))=0

We add all the numbers together, and all the variables

4(c+5)-(2(-1c+4))=0

We multiply parentheses

4c-(2(-1c+4))+20=0



We calculate terms in parentheses: -(2(-1c+4)), so:

2(-1c+4)

We multiply parentheses

-2c+8

Back to the equation:

-(-2c+8)



We get rid of parentheses

4c+2c-8+20=0

We add all the numbers together, and all the variables

6c+12=0

We move all terms containing c to the left, all other terms to the right

6c=-12

c=-12/6

c=-2

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