4(c+5)=3(c-6)

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Solution for 4(c+5)=3(c-6) equation: 



4(c+5)=3(c-6)

We move all terms to the left:

4(c+5)-(3(c-6))=0

We multiply parentheses

4c-(3(c-6))+20=0



We calculate terms in parentheses: -(3(c-6)), so:

3(c-6)

We multiply parentheses

3c-18

Back to the equation:

-(3c-18)



We get rid of parentheses

4c-3c+18+20=0

We add all the numbers together, and all the variables

c+38=0

We move all terms containing c to the left, all other terms to the right

c=-38

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