4(c+6)-58=3(2c-10)+40

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Solution for 4(c+6)-58=3(2c-10)+40 equation: 



4(c+6)-58=3(2c-10)+40

We move all terms to the left:

4(c+6)-58-(3(2c-10)+40)=0

We multiply parentheses

4c-(3(2c-10)+40)+24-58=0



We calculate terms in parentheses: -(3(2c-10)+40), so:

3(2c-10)+40

We multiply parentheses

6c-30+40

We add all the numbers together, and all the variables

6c+10

Back to the equation:

-(6c+10)



We add all the numbers together, and all the variables

4c-(6c+10)-34=0

We get rid of parentheses

4c-6c-10-34=0

We add all the numbers together, and all the variables

-2c-44=0

We move all terms containing c to the left, all other terms to the right

-2c=44

c=44/-2

c=-22

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