4(c-1)=-2(c+3)-28

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Solution for 4(c-1)=-2(c+3)-28 equation:


Simplifying
4(c + -1) = -2(c + 3) + -28

Reorder the terms:
4(-1 + c) = -2(c + 3) + -28
(-1 * 4 + c * 4) = -2(c + 3) + -28
(-4 + 4c) = -2(c + 3) + -28

Reorder the terms:
-4 + 4c = -2(3 + c) + -28
-4 + 4c = (3 * -2 + c * -2) + -28
-4 + 4c = (-6 + -2c) + -28

Reorder the terms:
-4 + 4c = -6 + -28 + -2c

Combine like terms: -6 + -28 = -34
-4 + 4c = -34 + -2c

Solving
-4 + 4c = -34 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
-4 + 4c + 2c = -34 + -2c + 2c

Combine like terms: 4c + 2c = 6c
-4 + 6c = -34 + -2c + 2c

Combine like terms: -2c + 2c = 0
-4 + 6c = -34 + 0
-4 + 6c = -34

Add '4' to each side of the equation.
-4 + 4 + 6c = -34 + 4

Combine like terms: -4 + 4 = 0
0 + 6c = -34 + 4
6c = -34 + 4

Combine like terms: -34 + 4 = -30
6c = -30

Divide each side by '6'.
c = -5

Simplifying
c = -5

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