4(c-1)=-6(c+2)+2c

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Solution for 4(c-1)=-6(c+2)+2c equation:


Simplifying
4(c + -1) = -6(c + 2) + 2c

Reorder the terms:
4(-1 + c) = -6(c + 2) + 2c
(-1 * 4 + c * 4) = -6(c + 2) + 2c
(-4 + 4c) = -6(c + 2) + 2c

Reorder the terms:
-4 + 4c = -6(2 + c) + 2c
-4 + 4c = (2 * -6 + c * -6) + 2c
-4 + 4c = (-12 + -6c) + 2c

Combine like terms: -6c + 2c = -4c
-4 + 4c = -12 + -4c

Solving
-4 + 4c = -12 + -4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4c' to each side of the equation.
-4 + 4c + 4c = -12 + -4c + 4c

Combine like terms: 4c + 4c = 8c
-4 + 8c = -12 + -4c + 4c

Combine like terms: -4c + 4c = 0
-4 + 8c = -12 + 0
-4 + 8c = -12

Add '4' to each side of the equation.
-4 + 4 + 8c = -12 + 4

Combine like terms: -4 + 4 = 0
0 + 8c = -12 + 4
8c = -12 + 4

Combine like terms: -12 + 4 = -8
8c = -8

Divide each side by '8'.
c = -1

Simplifying
c = -1

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