4(c-1)=5(c+2)

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Solution for 4(c-1)=5(c+2) equation:


Simplifying
4(c + -1) = 5(c + 2)

Reorder the terms:
4(-1 + c) = 5(c + 2)
(-1 * 4 + c * 4) = 5(c + 2)
(-4 + 4c) = 5(c + 2)

Reorder the terms:
-4 + 4c = 5(2 + c)
-4 + 4c = (2 * 5 + c * 5)
-4 + 4c = (10 + 5c)

Solving
-4 + 4c = 10 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
-4 + 4c + -5c = 10 + 5c + -5c

Combine like terms: 4c + -5c = -1c
-4 + -1c = 10 + 5c + -5c

Combine like terms: 5c + -5c = 0
-4 + -1c = 10 + 0
-4 + -1c = 10

Add '4' to each side of the equation.
-4 + 4 + -1c = 10 + 4

Combine like terms: -4 + 4 = 0
0 + -1c = 10 + 4
-1c = 10 + 4

Combine like terms: 10 + 4 = 14
-1c = 14

Divide each side by '-1'.
c = -14

Simplifying
c = -14

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