4(c-2)+17=3(c+5)

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Solution for 4(c-2)+17=3(c+5) equation: 



4(c-2)+17=3(c+5)

We move all terms to the left:

4(c-2)+17-(3(c+5))=0

We multiply parentheses

4c-(3(c+5))-8+17=0



We calculate terms in parentheses: -(3(c+5)), so:

3(c+5)

We multiply parentheses

3c+15

Back to the equation:

-(3c+15)



We add all the numbers together, and all the variables

4c-(3c+15)+9=0

We get rid of parentheses

4c-3c-15+9=0

We add all the numbers together, and all the variables

c-6=0

We move all terms containing c to the left, all other terms to the right

c=6

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