4(c-2)=3(c-1)

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Solution for 4(c-2)=3(c-1) equation:


Simplifying
4(c + -2) = 3(c + -1)

Reorder the terms:
4(-2 + c) = 3(c + -1)
(-2 * 4 + c * 4) = 3(c + -1)
(-8 + 4c) = 3(c + -1)

Reorder the terms:
-8 + 4c = 3(-1 + c)
-8 + 4c = (-1 * 3 + c * 3)
-8 + 4c = (-3 + 3c)

Solving
-8 + 4c = -3 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-8 + 4c + -3c = -3 + 3c + -3c

Combine like terms: 4c + -3c = 1c
-8 + 1c = -3 + 3c + -3c

Combine like terms: 3c + -3c = 0
-8 + 1c = -3 + 0
-8 + 1c = -3

Add '8' to each side of the equation.
-8 + 8 + 1c = -3 + 8

Combine like terms: -8 + 8 = 0
0 + 1c = -3 + 8
1c = -3 + 8

Combine like terms: -3 + 8 = 5
1c = 5

Divide each side by '1'.
c = 5

Simplifying
c = 5

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